Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
a2(f, a2(g, a2(f, x))) -> a2(f, a2(g, a2(g, a2(f, x))))
a2(g, a2(f, a2(g, x))) -> a2(g, a2(f, a2(f, a2(g, x))))
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
a2(f, a2(g, a2(f, x))) -> a2(f, a2(g, a2(g, a2(f, x))))
a2(g, a2(f, a2(g, x))) -> a2(g, a2(f, a2(f, a2(g, x))))
Q is empty.
Q DP problem:
The TRS P consists of the following rules:
A2(g, a2(f, a2(g, x))) -> A2(g, a2(f, a2(f, a2(g, x))))
A2(f, a2(g, a2(f, x))) -> A2(g, a2(g, a2(f, x)))
A2(g, a2(f, a2(g, x))) -> A2(f, a2(f, a2(g, x)))
A2(f, a2(g, a2(f, x))) -> A2(f, a2(g, a2(g, a2(f, x))))
The TRS R consists of the following rules:
a2(f, a2(g, a2(f, x))) -> a2(f, a2(g, a2(g, a2(f, x))))
a2(g, a2(f, a2(g, x))) -> a2(g, a2(f, a2(f, a2(g, x))))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
A2(g, a2(f, a2(g, x))) -> A2(g, a2(f, a2(f, a2(g, x))))
A2(f, a2(g, a2(f, x))) -> A2(g, a2(g, a2(f, x)))
A2(g, a2(f, a2(g, x))) -> A2(f, a2(f, a2(g, x)))
A2(f, a2(g, a2(f, x))) -> A2(f, a2(g, a2(g, a2(f, x))))
The TRS R consists of the following rules:
a2(f, a2(g, a2(f, x))) -> a2(f, a2(g, a2(g, a2(f, x))))
a2(g, a2(f, a2(g, x))) -> a2(g, a2(f, a2(f, a2(g, x))))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.